Inverse hyperbolic tangent integral

In this entry we prove the follwoing result, an integral I came across today in this video


\begin{align*} \int_0^1 \frac{\operatorname{arctanh}(x^2)}{x^2}\,dx&=\frac{\pi}{4}+\frac{\ln(2)}{2} \end{align*}


Click here for the proof.

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