Inverse hyperbolic tangent integral

In this entry we prove the follwoing result, an integral I came across today in this video


\begin{align*}
\int_0^1 \frac{\operatorname{arctanh}(x^2)}{x^2}\,dx&=\frac{\pi}{4}+\frac{\ln(2)}{2}
\end{align*}


Click here for the proof.

Comments

Popular posts from this blog